RhondaSommer
RhondaSommer RhondaSommer
  • 03-03-2017
  • Chemistry
contestada

Given a solution with a pOH of 13.6, what is the [OH-] of the solution?

13.6 M

2.51 x 10-14 M

0.4 M

3.98 x 10-1 M

Respuesta :

Аноним Аноним
  • 03-03-2017
10^-13.6 = 2.51x10^-14
Answer Link
mppalenciaa
mppalenciaa mppalenciaa
  • 29-08-2019

Answer:

2.51 x 10-14 M

Explanation:

The definition of pOH is:

pOH = -log[OH-]

then, clearing of the equation [OH-] we have:

-pOH = log[OH-]

By properties of logarithms:

[tex][OH-] = 10^{-pOH}[/tex]

Replacing the values:

[tex][OH-] = 10^{-13.6}[/tex]

And if you use a calculator, you will see that [tex]10^{-13.6}=2.51x10^{-14}[/tex]

Answer Link

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