Answer:
a. 165.5 V
b. 7.78 A
Explanation:
Here is the complete question
The RMS potential difference of an AC household outlet is 117 V. a) What is the maximum potential difference across a lamp connected to the outlet? b) If the RMS current through the lamp is 5.5 A, what is the maximun current through the lamp.
Solution
a. The maximum potential difference across the lamp Vā = ā2Vā where Vā = rms value of potential difference = 117 V
Vā = ā2Vā = ā2 Ć 117 V = 165.5 V
b. The maximum current through the lamp Iā = ā2Iā where Iā = rms value of current = 5.5 A
Vā = ā2Vā = ā2 Ć 5.5 A = 7.78 A
