Answer:
Explanation:
Given:
Four more crests pass in a time of 38.4 s and the distance between the crests is 32 m.
We have to determine five terms.
Lets start with one-one basis.
a. Ā
Period = Time taken by a wave to pass though.
ā Ā [tex]P = \frac{Total\ time}{No.\ of\ waves}[/tex]
ā [tex]P = \frac{38.4}{4}[/tex]
ā [tex]P=9.6 s[/tex]
b. Ā
Frequency = Reciprocal of time period in Hertz.
ā [tex]f=\frac{1}{T}[/tex]
ā[tex]f=\frac{1}{9.6}[/tex]
ā [tex]f=0.104 Hertz[/tex]
c)
Wavelength = Distance between two consecutive trough and crest.
ā [tex]\lambda = 32 m[/tex]
d.
Speed (v) = Product of frequency and wavelength.
ā [tex]v=f\times \lambda[/tex]
ā [tex]v=0.104\times 32[/tex]
ā[tex]v = 3.33 ms^-1[/tex]
e)
Amplitude = The maximum displacement or half the distance from crest to trough.
ā Here it can't be determined.
ā Impossible.
