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Gold forms face-centered cubic crystals. The atomic radius of a gold atom is 144 pm. Consider the face of a unit cell with the nuclei of the gold atoms at the lattice points. The atoms are in contact along the diagonal. Calculate the length of an edge of this unit cell.

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onyebuchinnaji

Answer:

The length of an edge of this unit cell is 407.294 pm

Explanation:

Face centered cubic structure contains 4 atoms in each unit cell and 12 coordination number, occupying about 74% volume of the total cell. Face centered cubic structure is known for efficient use of space for atom packing.

To determine the edge length, a relationship between the radius of the atom and edge length is used.

X = Rāˆš8

Where;

X is the length of an edge of this unit cell

R is the radius of the gold atom = 144 pm = 144 X 10ā»Ā¹Ā² m

X = 144 X 10ā»Ā¹Ā²āˆš8

X = 407.294 X 10ā»Ā¹Ā² m

X = 407.294 pm

Therefore, the length of an edge of this unit cell is 407.294 pm

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