Answer:
Ā Ā Ā Ā Ā Ā Ā Ā 275 kPa
Explanation:
Ā Ā Ā Ā Ā Ā Ā mass of the gas=m=1.5 kg
Ā Ā Ā Ā Ā Ā Ā initial volume if the gas=Vā=0.04 m³
Ā Ā Ā Ā Ā Ā Ā initial pressure of the gas= Pā=550 kPa
as the condition is given final volume is double the initial volume
Ā Ā Ā Ā Ā Ā Ā Vā=final volume
Ā Ā Ā Ā Ā Ā Ā Vā=2 Vā
As the temperature is constant
Ā Ā Ā Ā Ā Ā Ā Tā=Tā=T
[tex]\frac{P1V1}{T1}[/tex]=[tex]\frac{P2 V2}{T2}[/tex]
putting the values in the equation.
[tex]\frac{P1V1}{T1}[/tex]=[tex]\frac{P2 *2V1}{T2}[/tex]
Pā=[tex]\frac{P1}{2}[/tex]
Pā=[tex]\frac{550}{2}[/tex]
Pā=275 kPa
So the final pressure of the gas is 275 kPa.
Ā Ā Ā Ā Ā Ā