Answer:
a: z = -1.936
b: 0.0265
d: z < -1.645
Reject H0 if z < -1.645
Step-by-step explanation:
We are given:
H0:  µ = 20
HA:  µ < 20
n = 60, sample mean: 19.6, σ = 1.6
Since the alternate hypothesis has a < sign in it, it is a left tailed test. Â The < or > sign in the alternate hypothesis points towards the rejection region.
For a: Â We need to calculate the test statistic for our situation. Â This is done with a z-score formula for samples. Â
For b: Â we need to use the z-score table to look up the p-value for the score we calculate in part a. Â The p-value is 0.0265. Â This means that there is only about a 2.65% chance that the sample values were a result of random chance.
For d: Â Since the significance level is 0.05, and this is a one tailed test, we have a critical value of z < - 1.645. Â This means that if the z-score we calculate in part a is less than -1.645, we will reject the null hypothesis
See attached photo for all the calculations!