Answer:
The mass of the water in the fish tank is [tex]1.94\times 10^6\ g[/tex].
Explanation:
Given that,
Volume of the tank, [tex]V=1890\ L=1.89\times 10^6\ cm^3[/tex]
The density of seawater, [tex]d=1.03\ g/cm^3[/tex]
The density of any material is given by its mass per unit volume. Its relation is given by :
[tex]d=\dfrac{m}{V}[/tex]
m is the mass of the water in the fish tank
[tex]m=d\times V\\\\m=1.89\times 10^6\times 1.03\\\\m=1.94\times 10^6\ g[/tex]
So, the mass of the water in the fish tank is [tex]1.94\times 10^6\ g[/tex]. Hence, this is the required solution.
