Respuesta :

JonHenderson55
Answers:  
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Question  # 1) from first graph:
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The answer is:  " 3 " . 
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   →  [tex] \frac{AD}{AB} [/tex] ; in  "simplest form" , is:  " 3 " . 

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Question #2)  from second graph:
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The answer is:  " 4 " .
_____________________________________________________                  →   " (the slope of BE) over (the slope of AE) " ; 

        that is:  " (the slope of BE)  /  (the slope of AE) " ;

in  "simplest form" ,  is:  " 4 " . 
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Explanation:
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For Question #1) 

AD = 9 units (counted from the "attached graph"). 

AB = 3 units (counted from the "attached graph").
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We are asked to write:  "AD over AB" ; in "simplest form" ; 

     →   AD/AB  = " 9/3 " =  " (9÷3) / (3÷3) " = "(3/1)"  =  " 3 ÷ 1 " =  3 .
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     →   The answer is:  " 3 " .
_____________________________________________________                      →  "AD over AB" ; in "simplest form" ;   is:  " 3 " . 
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     →  AD/AB =  " 3 " .
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Question 2):  From second graph:
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Find the:  " (slope of BE) / (slope of AE) " ;  in "simplest form" :

From examination of the "second graph attached" :
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The "slope of BE" = rise/ run = 5/1 .

The "slope of AE" = rise/ run = 5/4 .
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So:  "(the slope of BE) / (the slope of AE)  ;

                                           = (5/1) / (5/4) ; 

                                            
                                           = [tex] \frac{5}{1} [/tex] ÷ [tex] \frac{5}{4}[/tex] ;

 → To divide a fraction, you multiply the "reciprocal of the fraction; as follows:

                                           = [tex] \frac{5}{1} [/tex] * [tex] \frac{4}{5}[/tex] ;

                       →  Both " 5 's "  cancel out to " 1 "; since: "{5 ÷ 5 = 1 }" ;  

                       →  And we can rewrite as:

                                           = [tex] \frac{1}{1} [/tex] * [tex] \frac{4}{1}[/tex] ;

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                                           =     1  *  4 ;

                                           =   " 4 " .
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                        →   The answer is:  " 4 " .
___________________________________________________________                           →  "AD over AE" ; in "simplest form" ;   is:  " 4 " . 
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